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Wednesday, 8 March 2017
Problem set 82
Two parallel plate capacitors, separated by distances x and 1.1x respectively, have a dielectric material of dielectric constant 3.0 inserted between the plates, and are connected to a battery of voltage V. The difference in charge on the second capacitor compared to the first is
+66%
+20%
-3.3%
-10%
Capacitance of a parallel plate capacitor is inversely proportional to the separation between the plates i.e. C\propto\frac{1}{d}C_1\propto\frac{1}{x}C_2\propto\frac{1}{1.1x}
Let us take area of plates such that
C_1=\frac{1}{x}C_2=\frac{1}{1.1x}C_2-C_1=\frac{1}{1.1x}-\frac{1}{x}=-\frac{0.1}{1.1x}\% difference=\frac{100\times\left(-\frac{0.1}{1.1x}\right)}{\frac{1}{1.1x}}\% difference=-10\%
Hence, answer is (D)
The state of a particle of mass m in a one-dimensional rigid box in the interval 0 to L is given by the normalised wavefunction \psi(x)\!=\!\!\sqrt{\frac{2}{L}}\!\!\left(\frac{3}{5}\sin{\left(\frac{2\pi x}{L}\right)}+\frac{4}{5}\sin{\left(\frac{4\pi x}{L}\right)}\!\right). If its energy is measured, the possible outcomes and the average value of energy are, respectively
\frac{h^2}{2mL^2}, \frac{2h^2}{mL^2} and \frac{73}{50}\frac{h^2}{mL^2}
\frac{h^2}{8mL^2}, \frac{h^2}{2mL^2} and \frac{19}{40}\frac{h^2}{mL^2}
\frac{h^2}{2mL^2}, \frac{2h^2}{mL^2} and \frac{19}{10}\frac{h^2}{mL^2}
\frac{h^2}{8mL^2}, \frac{2h^2}{mL^2} and \frac{73}{200}\frac{h^2}{mL^2}
Eigen function and energy of a particle in a 1D box are given by
\psi_n(x)=\sqrt{\frac{2}{L}}\sin{\left(\frac{n\pi x}{L}\right)}E_n=\frac{n^2h^2}{8mL^2}
Hence,
\psi(x)=c_2\psi_2(x)+c_4\psi_4(x)
where, c_2=\frac{3}{5} and c_4=\frac{4}{5} are the expansion coefficients.
Particle may be in its one of the eigenstate, hence possible values of energies are
E_2=\frac{2^2h^2}{8mL^2}=\frac{h^2}{2mL^2}E_4=\frac{4^2h^2}{8mL^2}=\frac{2h^2}{mL^2}
Average value of energy is
\begin{align*}
< E > &= < \psi |H|\psi > \\
&=|c_2|^2E_2+|c_4|^2E_4\\
&=\frac{9}{25}\frac{h^2}{2mL^2}+\frac{16}{25}\frac{2h^2}{mL^2}\\
&=\frac{73}{50}\frac{h^2}{mL^2}
\end{align*}
Hence, answer is (A)
If \hat L_x, \hat L_y and \hat L_z are the components of the angular momentum operator in three dimensions, the commutator \left[\hat L_x, \hat L_x\hat L_y\hat L_z\right] may be simplified to
The eigenstates corresponding to eigen-values E_1 and E_2 of a time-independent Hamiltonian are |1 > and |2 > respectively. If at t=0, the system is in a state |\psi(t=0) > =\sin\theta |1 > +\cos\theta |2 > the value of < \psi(t)|\psi(t) > at time t will be
Time evolution of quantum systems is given by Unitary Transformations,
\begin{align*}
\left|\psi(t)\right > &=\hat U\left|\psi(t=0)\right > \\
&=e^{-iHt/\hbar}\left\{\sin\theta \left|1\right > +\cos\theta \left|2\right > \right\}\\
&=\sin\theta e^{-\frac{iHt}{\hbar}}\left|1\right > +\cos\theta e^{-\frac{iHt}{\hbar}}\left|2\right >
\end{align*}
Using property f(\hat A)\psi_n=f(a_n)\psi_n we get
\begin{align*}
\left|\psi(t)\right > &=\sin\theta e^{-\frac{iE_1t}{\hbar}}\left|1\right > +\cos\theta e^{-\frac{iE_2t}{\hbar}}\left|2\right > \\
\end{align*}
Hence,
\left < \psi(t)\right|\left.\psi(t)\right > =\sin^2\theta+\cos^2\theta=1
Hence, answer is (A)
The specific heat per molecule of a gas of diatomic molecules at high temperatures is
8k_B
3.5k_B
4.5k_B
3k_B
At high temperatures, the specific heat at constant volume C_v has three degrees of freedom from rotation, two from translation, and two from vibration. Hence, f=7.
E=\frac{7}{2}RTC_v=\frac{dE}{dT}=\frac{7}{2}R
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